25 Pop Andrew Drive, Te Anau, 9600 is a Residential property built in 2004 with 3 bedrooms, 1 bathroom and 1 parking space. The property is estimated to be valued in the range of $600,000 to $650,000.
The property last sold on 17 July 2004 for $80,000. On 1 July 2024, 25 Pop Andrew Drive, Te Anau, 9600 had a Rating Valuation with a Capital Value of $660,000, Land Value of $240,000 and Improvement Value of $420,000.
Date | Type | Price | Agent/Agency |
---|---|---|---|
17 Jul 2004 | SOLD | $80,000 |
Lot 2 Deposited Plan 329683
There are no similar properties in the area that are listed for sale or recently sold.