18 Pop Andrew Drive, Te Anau, 9600 is a Residential property built in 1985 with 3 bedrooms, 1 bathroom and 3 parking spaces. The property is estimated to be valued in the range of $550,000 to $600,000.
The property last sold on 29 November 2021 for $560,000. On 1 July 2024, 18 Pop Andrew Drive, Te Anau, 9600 had a Rating Valuation with a Capital Value of $590,000, Land Value of $240,000 and Improvement Value of $350,000.
Date | Type | Price | Agent/Agency |
---|---|---|---|
29 Nov 2021 | SOLD | $560,000 | |
21 Dec 2001 | SOLD | $128,000 | |
27 Mar 1998 | SOLD | $110,000 |
Lot 5 Deposited Plan 14184
There are no similar properties in the area that are listed for sale or recently sold.